Nuclei - Result Question 35

36. In the reaction, 12H+13H24He+01n, if the binding energies of 12H,13H and 24He are respectively, a,b and c (in MeV ), then the energy (in MeV ) released in this reaction is

(a) a+b+c

(b) a+bc

(c) cab

(d) c+ab

[2005]

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Answer:

Correct Answer: 36. (c)

Solution:

  1. (c) 12H and 13H requires a and b amount of energies for their nucleons to be separated.

24He releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus.

Hence, Energy released =c(a+b)=cab



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