SATHEE: Nuclei - Result Question 32

Nuclei - Result Question 32

33. If $M (A; Z), M_{p}$ and $M_{n}$ denote the masses of the nucleus $_{Z}^{A} X$ , proton and neutron respectively in units of $u (1 u = 931.5 M e V / c^{2})$ and $B E$ represents its bonding energy in $M e V$ , then

[2008] (a) $M (A, Z) = Z M_{p} + (A - Z) M_{n} - B E / c^{2}$

(b) $M (A, Z) = Z M_{p}^{p} + (A - Z) M_{n} + B E$

(d) $M (A, Z) = Z M_{p}^{p} + (A - Z) M_{n} + B E / c^{2}$

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Answer:

Correct Answer: 33. (a)

Solution:

(a) Mass defect $= Z M_{p} + (A - Z) M_{n} - M (A, Z)$

or, $\frac{B . E}{c^{2}} = Z M_{p} + (A - Z) M_{n} - M (A, Z)$

$∴ M (A, Z) = Z M_{p} + (A - Z) M_{n} - \frac{B . E .}{c^{2}}$

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Nuclei - Result Question 32

33. If M(A;Z),Mp and Mn denote the masses of the nucleus ZAX, proton and neutron respectively in units of u(1u=931.5MeV/c2) and BE represents its bonding energy in MeV, then

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33. If $M (A; Z), M_{p}$ and $M_{n}$ denote the masses of the nucleus $_{Z}^{A} X$ , proton and neutron respectively in units of $u (1 u = 931.5 M e V / c^{2})$ and $B E$ represents its bonding energy in $M e V$ , then