SATHEE: Nuclei - Result Question 31

Nuclei - Result Question 31

32. The binding energy per nucleon in deuterium and helium nuclei are $1.1 M e V$ and $7.0 M e V$ , respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :

(a) $30.2 M e V$

(b) $23.6 M e V$

(d) $28.0 M e V$

[2010]

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Answer:

Correct Answer: 32. (b)

Solution:

(b) Binding energy of two $_{1} H^{2}$ nuclei

$= 2 (1.1 \times 2) = 4.4 M e V$

Binding energy of one $_{2} H e^{4}$ nucelus

$= 4 \times 7.0 = 28 M e V$

$∴$ Energy released $= 28 - 4.4 = 23.6 M e V$

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Nuclei - Result Question 31

32. The binding energy per nucleon in deuterium and helium nuclei are 1.1MeV and 7.0MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :

Answer:

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32. The binding energy per nucleon in deuterium and helium nuclei are $1.1 M e V$ and $7.0 M e V$ , respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :