Nuclei - Result Question 30
31. The mass of a $ _3^{7} Li$ nucleus is $0.042 u$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of $ _3^{7} Li$ nucleus is nearly
(a) $46 MeV$
(b) $5.6 MeV$
(c) $3.9 MeV$
(d) $23 MeV$
[2010]
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Answer:
Correct Answer: 31. (b)
Solution:
- (b) B.E. $=0.042 \times 931 \simeq 42 MeV$
Number of nucleons in $ _3^{7} Li$ is 7 .
$\therefore$ B.E. $/$ nucleon $=\frac{42}{7}=6 MeV \simeq 5.6 MeV$
