Nuclei - Result Question 25

26. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is

(Given : 1 a.m.u = $931 MeV$ )

[2013]

(a) $26.7 MeV$

(b) $6.675 MeV$

(c) $13.35 MeV$

(d) $2.67 MeV$

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Answer:

Correct Answer: 26. (b)

Solution:

  1. (b) Mass defect $\Delta m=0.02866$ a.m.u.

Energy $=0.02866 \times 931=26.7 MeV$

As $ _1 H^{2}+ _1 H^{2} \longrightarrow _2 He^{4}$

Energy liberated per a.m.u $=13.35 / 2 MeV$

$=6.675 MeV$



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