Nuclei - Result Question 25

26. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is

(Given : 1 a.m.u = 931MeV )

[2013]

(a) 26.7MeV

(b) 6.675MeV

(c) 13.35MeV

(d) 2.67MeV

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Answer:

Correct Answer: 26. (b)

Solution:

  1. (b) Mass defect Δm=0.02866 a.m.u.

Energy =0.02866×931=26.7MeV

As 1H2+1H22He4

Energy liberated per a.m.u =13.35/2MeV

=6.675MeV



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