Nuclei - Result Question 18

20. The nuclei 6C13 and 7N14 can be described as

(a) isotones

(b) isobars

(c) isotopes of carbon

(d) isotopes of nitrogen

[1990]

Show Answer

Answer:

Correct Answer: 20. (a)

Solution:

  1. (a) As6C13 and 7N14 have same no. of neutrons (13−6=7 for C and 14−7=7 for N ), so they are isotones.
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