SATHEE: Nuclei - Result Question 11

Nuclei - Result Question 11

11. Atomic weight of Boron is 10.81 and it has two isotopes $_{5} B^{10}$ and $_{5} B^{11}$ . Then the ratio $_{5} B^{10} :_{5} B^{11}$ in nature would be

[1998]

(a) $19 : 81$

(b) $10 : 11$

(d) $81 : 19$

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Answer:

Correct Answer: 11. (a)

Solution:

(a) Suppose that,

The number of $^{10} B$ type atoms $= x$

and the number of $^{11} B$ type atoms $= y$

Weight of $^{10} B$ type atoms $= 10 x$

Weight of $^{11} B$ type atoms $= 11 y$

Total number of atoms $= x + y$

$∴$ Atomic weight $= \frac{10 x + 11 y}{x + y} = 10.81$

$\Rightarrow 10 x + 11 y = 10.81 x + 10.81 y$

$\Rightarrow 0.81 x = 0.19 y \Rightarrow \frac{x}{y} = \frac{19}{81}$

If relative abundance of isotopes in an element has ratio $n_{1} : n_{2}$ whose atomic massers are $m_{1}$ and $m_{2}$ then atomic masses of elements is

$M = \frac{n_{1} m_{1} + n_{2} m_{2}}{n_{1} + n_{2}}$

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Nuclei - Result Question 11

11. Atomic weight of Boron is 10.81 and it has two isotopes 5B10 and 5B11. Then the ratio 5B10:5B11 in nature would be

Answer:

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11. Atomic weight of Boron is 10.81 and it has two isotopes $_{5} B^{10}$ and $_{5} B^{11}$ . Then the ratio $_{5} B^{10} :_{5} B^{11}$ in nature would be