Nuclei - Result Question 1

1. If radius of the 1227Al nucleus is taken to be RAl, then the radius of 53125Te nucleus is nearly:

[2015]

(a) 53RAl

(b) 35RAl

(c) (1353)1/3RAl

(d) (5313)1/3RAl

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Solution:

  1. (a) As we know, R=R0(A)1/3

where A= mass number

RAI=R0(27)1/3=3R0

RTe=R0(125)1/3=5R0=53RAI



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