Moving Charges and Magnetism - Result Question 57

58. A 250-turn rectangular coil of length 2.1cm and width 1.25cm carries a current of 85μA and subjected to magnetic field of strength 0.85 T. Work done for rotating the coil by 180∘ against the torque is

(a) 4.55μJ

(c) 1.15μJ

(b) 2.3μJ

(d) 9.1μJ

[2017]

Show Answer

Answer:

Correct Answer: 58. (d)

Solution:

  1. (d) Work done, W=MB(cos⁡θ1−cos⁡θ2)

When it is rotated by angle 180∘ then

W=MB(cos⁡0∘−cos⁡180∘)=MB(1+1)

W=2MB

W=2 (NIA) B

=2×250×85×10−6[1.25×2.1×10−4]×85×

10−2

=9.1μJ

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