SATHEE: Motion in a Straight Line

Motion in a Straight Line - Result Question 49

51. What will be the ratio of the distances moved by a freely falling body from rest in 4th and 5th seconds of journey?

[1989]

(a) $4 : 5$

(b) $7 : 9$

(d) $1 : 1$

Show Answer

Answer:

Correct Answer: 51. (b)

Solution:

(b) $\frac{x (4)}{x (5)} = \frac{\frac{g}{2} (2 \times 4 - 1)}{\frac{g}{2} (2 \times 5 - 1)} = \frac{7}{9}$

$[∵ S_{n^{th}} = u + \frac{a}{2} (2 n - 1) .$ and $. u = 0, a = g]$

In the absence of air resistance, all bodies irrespective of the size, weight or composition fall with the same acceleration near the surface of the earth. This motion of a body falling towards the earth from a small altitude $(h « R)$ is called free fall.

Distance travelled in nth second $h_{n} = \frac{g}{2} (2 n - 1)$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Motion in a Straight Line - Result Question 49

51. What will be the ratio of the distances moved by a freely falling body from rest in 4th and 5th seconds of journey?

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu