SATHEE: Motion in a Straight Line

Motion in a Straight Line - Result Question 39

40. A man of $50 k g$ mass is standing in a gravity free space at a height of $10 m$ above the floor. $H e$ throws a stone of $0.5 k g$ mass downwards with a speed $2 m / s$ . When the stone reaches the floor, the distance of the man above the floor will be:

(a) $9.9 m$

(b) $10.1 m$

(d) $20 m$

[2010]

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Answer:

Correct Answer: 40. (b)

Solution:

(b) No external force is acting, therefore, momentum is conserved.

By momentum conservation,

$50 u + 0.5 \times 2 = 0$

where $u$ is the velocity of man.

$u = - \frac{1}{50} m s^{- 1}$

Negative sign of $u$ shows that man moves upward.

Time taken by the stone to reach the ground

$= \frac{10}{2} = 5 s e c$

tance moved by the man $= 5 \times \frac{1}{50} = 0.1 m$

$∴$ when the stone reaches the floor, the distance of the man above floor $= 10.1 m$

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Motion in a Straight Line - Result Question 39

40. A man of 50kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed 2m/s. When the stone reaches the floor, the distance of the man above the floor will be:

Answer:

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40. A man of $50 k g$ mass is standing in a gravity free space at a height of $10 m$ above the floor. $H e$ throws a stone of $0.5 k g$ mass downwards with a speed $2 m / s$ . When the stone reaches the floor, the distance of the man above the floor will be: