Motion in a Straight Line - Result Question 36

37. A stone falls freely under gravity. It covers distances $h_1, h_2$ and $h_3$ in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between $h_1, h_2$ and $h_3$ is

(a) $h_1=\frac{h_2}{3}=\frac{h_3}{5}$

[2013]

(b) $h_2=3 h_1$ and $h_3=3 h_2$

(c) $h_1=h_2=h_3$

(d) $h_1=2 h_2=3 h_3$

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Answer:

Correct Answer: 37. (a)

Solution:

  1. (a) $\because \quad h=\frac{1}{2} g t^{2}$

$\therefore \quad h_1=\frac{1}{2} g(5)^{2}=125$

$h_1+h_2=\frac{1}{2} g(10)^{2}=500$

$\Rightarrow h_2=375$

$ h_1+h_2+h_3=\frac{1}{2} g(15)^{2}=1125 $

$\Rightarrow h_3=625$

$h_2=3 h_1, h_3=5 h_1$

or $\quad h_1=\frac{h_2}{3}=\frac{h_3}{5}$

The distance covered in time $t, 2 t, 3 t$, etc. will be in the ratio of $1^{2}: 2^{2}: 3^{2}$ i.e., square of integers i.e., $h$ $\propto t^{2}$.



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