Motion in a Straight Line - Result Question 26
27. The displacement of a particle varies with time (t) as: $s=a t^{2}-b t^{3}$. The acceleration of the particle will be zero at time $t$ equal to [1997]
(a) $\frac{a}{b}$
(b) $\frac{a}{3 b}$
(c) $\frac{3 b}{a}$
(d) $\frac{2 a}{3 b}$
Show Answer
Answer:
Correct Answer: 27. (b)
Solution:
- (b) distance, $s=a t^{2}-b t^{3}$
