SATHEE: Motion in a Straight Line

Motion in a Straight Line - Result Question 11

(a) $2 m$

(b) $4 m$

(d) $6 m$

[NEET Kar. 2013]

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Answer:

Correct Answer: 11. (c)

Solution:

$\Rightarrow \sqrt{x} = t - 3 \Rightarrow x = (t - 3)^{2}$

$v = \frac{d x}{d t} = 2 (t - 3) = 0$

$\Rightarrow t = 3$

From equation (i)

$∴ x = (3 - 3)^{2}$

$\Rightarrow x = 0$

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Motion in a Straight Line - Result Question 11

11. The displacement ’ x ’ (in meter) of a particle of mass ’ m ’ (in kg) moving in one dimension under the action of a force, is related to time ’ t ’ (in sec) by t=x+3. The displacement of the particle when its velocity is zero, will be

Answer:

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11. The displacement ’ $x$ ’ (in meter) of a particle of mass ’ $m$ ’ (in kg) moving in one dimension under the action of a force, is related to time ’ $t$ ’ (in sec) by $t = \sqrt{x} + 3$ . The displacement of the particle when its velocity is zero, will be