Motion in a Plane - Result Question 44
47. A particle moves in a circle of radius $5 cm$ with constant speed and time period $0.2 \pi s$. The acceleration of the particle is
(a) $15 m / s^{2}$
(b) $25 m / s^{2}$
(c) $36 m / s^{2}$
(d) $5 m / s^{2}$
[2011]
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Answer:
Correct Answer: 47. (d)
Solution:
- (d) Centripetal acceleration $a_c=\omega^{2} r$
$=(\frac{2 \pi}{T})^{2} r=(\frac{2 \pi}{0.2 \pi})^{2} \times 5 \times 10^{-2}=5 m / s^{2}$
