Motion in a Plane - Result Question 38
41. The maximum range of a gun of horizontal terrain is $16 km$. If $g=10 ms^{-2}$, then muzzle velocity of a shell must be
[1990]
(a) $160 ms^{-1}$
(b) $200 \sqrt{2} ms^{-1}$
(c) $400 ms^{-1}$
(d) $800 ms^{-1}$
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Answer:
Correct Answer: 41. (c)
Solution:
- (c) $R _{\max }=\frac{v^{2}}{g}=16000[16 km=16000 m]$ or $v=(16000 g)^{1 / 2}=(16000 \times 10)^{1 / 2}=400 ms^{-1}$
