Motion in a Plane - Result Question 16

18. Find the torque of a force F=3i^+j^+5k^ acting at the point r=7i^+3j^+k^.

[1997]

(a) 21i^+3j^+5k^

(b) 14i^+3j^+16k^

(c) 4i^+4j^+6k^

(d) 14i^38j^+16k^

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Answer:

Correct Answer: 18. (d)

Solution:

  1. (d) F=3i^+j^+5k^;r=7i^+3j^+k^

Torque (τ)=r×F

=(7i^+3j^+k^)×(3i^+j^+5k^)

=7k^+35(j^)9(k^)+15i^3j^+(i^)

=14i^38j^+16k^



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