Motion in a Plane - Result Question 12

14. A particle moves with a velocity v=6i^4j^+3k^m/s under the influence of a constant force F=20i^+15j^5k^N. The instantaneous power applied to the particle is

(a) 45J/s

(b) 35J/s

(c) 25J/s

(d) 195J/s

[2000]

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Answer:

Correct Answer: 14. (a)

Solution:

  1. (a) As we know,

P=Fv=(6i^4j^+3k^)(20i^+15j^5k^)=6×204×153×5=45J/s

Instantanesous power can be calculated by

Pins =Fcosθv=Fv

which is the scalar product of force and velocity vector.



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