Mechanical Properties of Solids - Result Question 9

10. The bulk modulus of a spherical object is ’ $B$ ‘. If it is subjected to uniform pressure ’ $p$ ‘, the fractional decrease in radius is

[2017]

(a) $\frac{B}{3 p}$

(b) $\frac{3 p}{B}$

(c) $\frac{p}{3 B}$

(d) $\frac{p}{B}$

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Solution:

  1. (c) Bulk modulus is given by

$B=\frac{p}{(\frac{\Delta V}{V})} \quad$ or $\quad \frac{\Delta V}{V}=\frac{p}{B}$

$3 \frac{\Delta R}{R}=\frac{p}{B}$ (here, $\frac{\Delta R}{R}=$ fractional decreases in radius) $\Rightarrow \frac{\Delta R}{R}=\frac{p}{3 B}$

If the object of mass $m$ and radius $r$ is sorrounded by a liquid in a cylindrical container

$\frac{\Delta R}{R}=\frac{1}{3} \frac{\Delta V}{V}$

Bulk modulus, $K=-V \frac{\Delta P}{\Delta V}$

$ \begin{aligned} & \therefore \frac{\Delta V}{V}=\frac{\Delta P}{K}=\frac{m g}{A K} \quad(\because \Delta P=\frac{m g}{A}) \\ & \therefore \frac{\Delta R}{R}=\frac{1}{3} \frac{m g}{A K} \quad(\text{ Here } A=\text{ area of object }) \end{aligned} $



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