SATHEE: Mechanical Properties of Solids

Mechanical Properties of Solids - Result Question 2

2. The stress-strain curves are drawn for two different materials $X$ and $Y$ . It is observed that the ultimate strength point and the fracture point are close to each other for material $X$ but are far apart for material $Y$ .

We can say that materials $X$ and $Y$ are likely to be (respectively),

[NEET Odisha 2019]

(a) Plastic and ductile

(b) Ductile and brittle

(d) Brittle and plastic

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Solution:

(c) Fracture point and ultimate strength point is close for material $X$ , hence $X$ is brittle in nature and both points are far apart for material $Y$ hence it is ductile.

(a) Wire 1: $\overset{⏞}{A, 3 ℓ} F$

$\begin{matrix} (i) & Δ ℓ = (\frac{F}{A Y}) 3 ℓ \end{matrix}$

Wire 2:

$\begin{matrix} (ii) & Δ ℓ = (\frac{F^{'}}{3 A Y}) ℓ \end{matrix}$

From equation (i) & (ii),

$Δ ℓ = (\frac{F}{A Y}) 3 ℓ = (\frac{F^{'}}{3 A Y}) ℓ or, F^{'} = 9 F$

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Mechanical Properties of Solids - Result Question 2

2. The stress-strain curves are drawn for two different materials X and Y. It is observed that the ultimate strength point and the fracture point are close to each other for material X but are far apart for material Y.

Solution:

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2. The stress-strain curves are drawn for two different materials $X$ and $Y$ . It is observed that the ultimate strength point and the fracture point are close to each other for material $X$ but are far apart for material $Y$ .