Mechanical Properties of Fluids - Result Question 6
6. The compressibility of water is $4 \times 10^{-5}$ per unit atmospheric pressure. The decrease in volume of $100 cm^{3}$ of water under a pressure of 100 atmosphere will be
(a) $0.4 cm^{3}$
(c) $0.025 cm^{3}$
(b) $4 \times 10^{-5} cm^{3}$
(d) $0.004 cm^{3}$
[1990]
Topic 2: Fluid Flow, Reyonld’s Number & Bernoulli’s Principle
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Answer:
Correct Answer: 6. (a)
Solution:
- (a) $K=\frac{1}{B}=\frac{\Delta V / V}{P}$. Here, $P=100 atm$,
$K=4 \times 10^{-5}$ and $V=100 cm^{3}$.
Hence, $\Delta V=0.4 cm^{3}$
