Laws of Motion - Result Question 7

7. A 0.5kg ball moving with speed of 12m/s strikes a hard wall at an angle of 30 with the wall. It is reflected with the same speed and at the same angle. If the ball is in contact with the wall for 0.25 seconds, the average force acting on the wall is

[2006]

(a) 24N

(b) 12N

(c) 96N

(d) 48N

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Answer:

Correct Answer: 7. (a)

Solution:

  1. (a)

The magnetitude of both velocity v1 and v2 are equal. Components of velocity along the wall are equal and are in same direction.

But the component of velocity perpendicular to wall are equal but opposite in direction.

So, net change in momentum in perpendicular direction,

ΔP=mv1sin30(mv2sin30)

2mvsin30[|v1|v2]

Average force acting on the wall will be given by

Fxt=2mvsin30F=2mvsin30tF=2×0.52×12×12×0.25=24F=24N



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