Laws of Motion - Result Question 6

6. Sand is being dropped on a conveyor belt at the rate of Mkg/s. The force necessary to keep the belt moving with a constant velocity of vm/s will be:

[2008]

(a) Mv newton

(b) 2 Mv newton

(c) Mv2 newton

(d) zero

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Answer:

Correct Answer: 6. (a)

Solution:

(a) F=d(Mv)dt=Mdvdt+vdMdt

v is constant,

F=vdMdt But dMdt=Mkg/s

F=vM newton.



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