Laws of Motion - Result Question 47
47. A block of mass $1 kg$ is placed on a truck which accelerates with acceleration $5 m / s^{2}$. The coefficient of static friction between the block and truck is 0.6 . The frictional force acting on the block is
(a) $5 N$
(b) $6 N$
(c) $5.88 N$
(d) $4.6 N$
[2001]
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Answer:
Correct Answer: 47. (a)
Solution:
- (a) Maximum friction force $=\mu mg$
$=.6 \times 1 \times 9.8=5.88 N$
But here required friction force
$=ma=1 \times 5=5 N$
For a body placed on a moving body and Ist body not to slide - applied force $F<$ limiting friction ( $=$ Ms mg) combined system will move together with common acceleration $a_1=a_2=\frac{F}{M+m}$.
