SATHEE: Laws of Motion - Result Question 44

Laws of Motion - Result Question 44

44. A block of mass $m$ is in contact with the cart $C$ as shown in the Figure.

[2010]

The coefficient of static friction between the block and the cart is $μ$ . The acceleration $α$ of the cart that will prevent the block from falling satisfies:

(a) $α > \frac{m g}{μ}$

(b) $α > \frac{g}{μ m}$

(d) $α < \frac{g}{μ}$

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Answer:

Correct Answer: 44. (c)

Solution:

(c) Forces acting on the block are as shown in the fig. Normal reaction $N$ is provided by the force ma due to acceleration $α$

$∴ N = m a$ For the block not to fall, frictional force, $F_{f} \geq m g$

$\Rightarrow μ N \geq m g$

$\Rightarrow μ m a \geq m g$

$\Rightarrow a \geq g / μ$

When a cart moves with some acceleration towards right then a psendo force (ma) acts on block towards left. This force ma is action force by a block on cart.

Laws of Motion - Result Question 44

44. A block of mass $m$ is in contact with the cart $C$ as shown in the Figure.

Answer:

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Laws of Motion - Result Question 44

44. A block of mass m is in contact with the cart C as shown in the Figure.

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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44. A block of mass $m$ is in contact with the cart $C$ as shown in the Figure.