Laws of Motion - Result Question 32
32. A monkey of mass $20 kg$ is holding a vertical rope. The rope will not break when a mass of 25 $kg$ is suspended from it but will break if the mass exceeds $25 kg$. What is the maximum acceleration with which the monkey can climb up along the rope? $(g=10 m / s^{2})$
[2003]
(a) $2.5 m / s^{2}$
(b) $5 m / s^{2}$
(c) $10 m / s^{2}$
(d) $25 m / s^{2}$
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Answer:
Correct Answer: 32. (a)
Solution:
- (a) $T=$ Tension caused in string by monkey $=m(g+a)$
$\therefore T \leq 25 \times 10 \Rightarrow 20(10+a) \leq 250$
or, $10+a \leq 12.5 \Rightarrow a \leq 2.5$
