Laws of Motion - Result Question 31

31. A man weighing $80 kg$, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$. What would be the reading on the scale? $(g=10 m / s^{2})$ [2003]

(a) $1200 N$

(b) zero

(c) $400 N$

(d) $800 N$

Show Answer

Answer:

Correct Answer: 31. (a)

Solution:

  1. (a) Reading of the scale = Apparent wt. of the man $=m(g+a)$ $=80(10+5)=1200 N$


NCERT Chapter Video Solution

Dual Pane