SATHEE: Laws of Motion - Result Question 3

Laws of Motion - Result Question 3

3. A stone is dropped from a height $h$ . It hits the ground with a certain momentum $P$ . If the same stone is dropped from a height $100$ more than the previous height, the momentum when it hits the ground will change by :

[2012M]

(a) $68$

(b) $41$

(d) $100$

Show Answer

Answer:

Correct Answer: 3. (b)

Solution:

(b) Momentum $P = m v = m \sqrt{2 g h}$

$(∵ v^{2} = u^{2} + 2 g h; .$ Here $. u = 0)$

When stone hits the ground momentum,

$P = m \sqrt{2 g h}$

when same stone dropped from $2 h (100$ of initial) then momentum,

$P^{'} = m \sqrt{2 g (2 h)} = \sqrt{2} P$

$50$ change in momentum, $\frac{(P^{'} - P)}{P} \times 100$ $\Rightarrow (\frac{\sqrt{2} P - P}{P}) \times 100$

$\Rightarrow (1.414 - 1) \times 100$

$\Rightarrow 414 \times 100$

Which is changed by $41$ of initial.

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Laws of Motion - Result Question 3

3. A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100 more than the previous height, the momentum when it hits the ground will change by :

Answer:

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3. A stone is dropped from a height $h$ . It hits the ground with a certain momentum $P$ . If the same stone is dropped from a height $100$ more than the previous height, the momentum when it hits the ground will change by :