Laws of Motion - Result Question 29

29. The coefficient of static friction, μs, between block A of mass 2kg and the table as shown in the figure is 0.2 . What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.

(g=10m/s2)

(a) 0.4kg

(b) 2.0kg

(c) 4.0kg

(d) 0.2kg

Show Answer

Answer:

Correct Answer: 29. (a)

Solution:

  1. (a) Condition for the max value of mass of block B so that two blocks do not move is,

mBg=μsmAg

⇒mB=μsmA

or, mB=0.2×2=0.4kg

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