SATHEE: Laws of Motion - Result Question 27

Laws of Motion - Result Question 27

27. Three forces acting on a body are shown in the figure. To have the resultant force only along the $y$ - direction, the magnitude of the minimum additional force needed is:

[2008]

(a) $0.5 N$

(b) $1.5 N$

(d) $\sqrt{3} N$

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Answer:

Correct Answer: 27. (a)

Solution:

(a) The components of $1 N$ and $2 N$ forces along $+ x$ -axis $= 1 \cos 60^{\circ} + 2 \sin 30^{\circ}$

$= 1 \times \frac{1}{2} + 2 \times \frac{1}{2} = \frac{1}{2} + 1 = \frac{3}{2} = 1.5 N$

The component of $4 N$ force along $- x$ -axis

$= 4 \sin 30^{\circ} = 4 \times \frac{1}{2} = 2 N$ .

Therefore, if a force of $0.5 N$ is applied along $+ x$ axis, the resultant force along $x$ -axis will become zero and the resultant force will be obtained only along $y$ -axis.

Laws of Motion - Result Question 27

27. Three forces acting on a body are shown in the figure. To have the resultant force only along the $y$ - direction, the magnitude of the minimum additional force needed is:

Answer:

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Laws of Motion - Result Question 27

27. Three forces acting on a body are shown in the figure. To have the resultant force only along the y - direction, the magnitude of the minimum additional force needed is:

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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27. Three forces acting on a body are shown in the figure. To have the resultant force only along the $y$ - direction, the magnitude of the minimum additional force needed is: