Laws of Motion - Result Question 26
26. A person of mass $60 kg$ is inside a lift of mass $940 kg$ and presses the button on control panel. The lift starts moving upwards with an acceleration $1.0 m / s^{2}$. If $g=10 ms^{-2}$, the tension in the supporting cable is
(a) $8600 N$
(b) $9680 N$
(c) $11000 N$
(d) $1200 N$
[2011]
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Answer:
Correct Answer: 26. (c)
Solution:
- (c)
Total mass $=(m+m)=(60+940) kg=1000 kg$
Let $T$ be the tension in the supporting cable, then
$ \begin{aligned} & T-1000 g=1000 \times 1 \quad[\because a=1 m / sec] \\ & \Rightarrow T=11000 N \end{aligned} $
