Laws of Motion - Result Question 22

22. Three blocks A, B and C of masses 4kg,2kg and 1kg respectively, are in contact on a frictionless surface, as shown. If a force of 14N is applied on the 4kg block then the contact force between A and B is

[2015]

(a) 6N

(b) 8N

(c) 18N

(d) 2N

Show Answer

Answer:

Correct Answer: 22. (a)

Solution:

  1. (a) Acceleration of system, a=Fnet Mtotal  =144+2+1=147=2m/s2

The contact force between A and B

=(mB+mC)×a=(2+1)×2=6N



NCERT Chapter Video Solution

Dual Pane