SATHEE: Laws of Motion - Result Question 17

Laws of Motion - Result Question 17

17. A $600 k g$ rocket is set for a vertical firing. If the exhaust speed is $1000 m s^{- 1}$ , the mass of the gas ejected per second to supply the thrust needed to overcome the weight of rocket is

(a) $117.6 k g s^{- 1}$

(b) $58.6 k g s^{- 1}$

(d) $76.4 k g s^{- 1}$

[1990]

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Answer:

Correct Answer: 17. (c)

Solution:

$\Rightarrow \frac{u d M}{d t} = m g \Rightarrow \frac{d M}{d t} = \frac{m g}{u}$

$= \frac{600 \times 10}{1000} = 6 k g s^{- 1}$

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Laws of Motion - Result Question 17

17. A 600kg rocket is set for a vertical firing. If the exhaust speed is 1000ms−1, the mass of the gas ejected per second to supply the thrust needed to overcome the weight of rocket is

Answer:

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17. A $600 k g$ rocket is set for a vertical firing. If the exhaust speed is $1000 m s^{- 1}$ , the mass of the gas ejected per second to supply the thrust needed to overcome the weight of rocket is