SATHEE: Kinetic Theory - Result Question 7

Kinetic Theory - Result Question 7

7. A gas at $27^{\circ} C$ temperature and 30 atmospheric pressure is allowed to expand to the atmospheric pressure. If the volume becomes 10 times its initial volume, then the final temperature becomes

(a) $100^{\circ} C$

(b) $173^{\circ} C$

(d) $- 173^{\circ} C$

[2001]

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Answer:

Correct Answer: 7. (d)

Solution:

(d) Given : Initial temperature of gas

$(T_{1}) = 27^{\circ} C = 300 K$

Initial pressure $(P_{1}) = 30 a t m$

Initial volume $(V_{1}) = V$

Final pressure $(P_{2}) = 1 a t m$

Final volume $(V_{2}) = 10 V$ .

We know from the general gas equation that $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ or, $\frac{30 \times V}{300} = \frac{1 \times 10 V}{T_{2}}$

or, $T_{2} = 100 K = - 173^{\circ} C$ .

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Kinetic Theory - Result Question 7

7. A gas at 27∘C temperature and 30 atmospheric pressure is allowed to expand to the atmospheric pressure. If the volume becomes 10 times its initial volume, then the final temperature becomes

Answer:

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7. A gas at $27^{\circ} C$ temperature and 30 atmospheric pressure is allowed to expand to the atmospheric pressure. If the volume becomes 10 times its initial volume, then the final temperature becomes