SATHEE: Kinetic Theory - Result Question 22

Kinetic Theory - Result Question 22

22. The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :

[2020]

(a) $\frac{1}{\sqrt{2} n π d^{2}}$

(b) $\frac{1}{\sqrt{2} n^{2} π d^{2}}$

(d) $\frac{1}{\sqrt{2} n π d}$

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Answer:

Correct Answer: 22. (a)

Solution:

(a) Mean free path for a gas $λ_{m} = \frac{1}{\sqrt{2} n π d^{2}}$

Here, $d =$ diameter of a gas molecule and, $n =$ molecular density.

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Kinetic Theory - Result Question 22

22. The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

Answer:

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22. The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :