SATHEE: Kinetic Theory - Result Question 14

Kinetic Theory - Result Question 14

14. In a vessel, the gas is at a pressure $P$ . If the mass of all the molecules is halved and their speed is doubled, then the resultant pressure will be

(a) $4 P$

(b) $2 P$

(d) $P / 2$

[NEET Kar: 2013]

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Answer:

Correct Answer: 14. (b)

Solution:

(b) $∵ P = \frac{1}{3} \frac{m N}{V} v_{r} m s^{2}$

where $m =$ mass of each molecules

$N =$ total number of molecules

$V =$ volume of the gas

When mass is halved and speed is doubled then

Resultant pressure, $P^{'} = \frac{1}{3} \times (\frac{m}{2}) \times \frac{N}{V} (2 v_{r m s})^{2}$

$= 2 P$

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Kinetic Theory - Result Question 14

14. In a vessel, the gas is at a pressure P. If the mass of all the molecules is halved and their speed is doubled, then the resultant pressure will be

Answer:

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14. In a vessel, the gas is at a pressure $P$ . If the mass of all the molecules is halved and their speed is doubled, then the resultant pressure will be