Gravitation - Result Question 59
62. For a satellite escape velocity is $11 km / s$. If the satellite is launched at an angle of $60^{\circ}$ with the vertical, then escape velocity will be [1989]
(a) $11 km / s$
(b) $11 \sqrt{3} km / s$
(c) $\frac{11}{\sqrt{3}} km / s$
(d) $33 km / s$
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Solution:
- (a) Since, escape velocity $(v_e=\sqrt{2 g R_e})$ is independent of angle of projection, so it will not change.
