Gravitation - Result Question 58

61. If the gravitational force between two objects were proportional to 1/R (and not as 1/R2 ) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to

(a) 1/R2 (b) R0 (c) R1 (d) 1/R

[1989]

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Solution:

(b) F=kR=Mv2R. Hence vR0



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