SATHEE: Gravitation - Result Question 52

Gravitation - Result Question 52

55. The escape velocity from the surface of the earth is $v_{e}$ . The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be

(a) $v_{e}$

(b) $3 v_{e}$

(d) $1 / 3 v_{e}$

[1995]

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Answer:

Correct Answer: 55. (a)

Solution:

(a) Escape velocity on surface of earth

$\begin{aligned} v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}} \propto \sqrt{\frac{M_{e}}{R_{e}}} . \\ ∴ \frac{v_{e}}{v_{P}} = \sqrt{\frac{M_{e}}{R_{e}}} \times \sqrt{\frac{R_{p}}{M_{p}}} \\ = \sqrt{\frac{M_{e}}{R_{e}}} \times \sqrt{\frac{3 R_{e}}{3 M_{e}}} = \frac{1}{1} = 1 \end{aligned}$

or, $v_{P} = v_{e}$ .

Gravitation - Result Question 52

55. The escape velocity from the surface of the earth is $v_{e}$ . The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be

Answer:

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Gravitation - Result Question 52

55. The escape velocity from the surface of the earth is ve. The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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55. The escape velocity from the surface of the earth is $v_{e}$ . The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be