Gravitation - Result Question 4

4. The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun?

[1997]

(a) 2

(b) 3

(c) 4

(d) 5

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Answer:

Correct Answer: 4. (a)

Solution:

  1. (a) Let TA and TB be time period of A and B about sun.

TA=8TB

TATB=8

According to Kepler’s Law, T2r3

TATB=(rA)3(rB)3(rArB)3=8rArB=2



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