SATHEE: Gravitation - Result Question 16

Gravitation - Result Question 16

16. The height at which the weight of a body becomes $1 / 16$ th, its weight on the surface of earth (radius $R$ ), is :

[2012]

(a) $5 R$

(b) $15 R$

(d) $4 R$

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Answer:

Correct Answer: 16. (c)

Solution:

$\Rightarrow \frac{1}{(R + h)^{2}} = \frac{1}{16 R^{2}}$

$\Rightarrow \frac{R}{(R + h)} = \frac{1}{4}$

$\Rightarrow \frac{R + h}{R} = 4$

$\Rightarrow h = 3 R$

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Gravitation - Result Question 16

16. The height at which the weight of a body becomes 1/16 th, its weight on the surface of earth (radius R ), is :

Answer:

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16. The height at which the weight of a body becomes $1 / 16$ th, its weight on the surface of earth (radius $R$ ), is :