Gravitation - Result Question 11
11. A spherical planet has a mass $M_P$ and diameter $D_P$. A particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity, equal to: [2012]
(a) $4 G M_P / D_P^{2}$
(b) $G M_P m / D_P^{2}$
(c) $G M_P / D_P^{2}$
(d) $4 G M_P m / D_P^{2}$
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Answer:
Correct Answer: 11. (a)
Solution:
- (a) Gravitational attraction force on particle B,
$F_g=\frac{G M_P m}{(D_P / 2)^{2}}$
Acceleration of particle due to gravity
$a=\frac{F_g}{m}=\frac{4 G M_P}{D_P^{2}}$
