Electrostatic Potential and Capacitance - Result Question 47
49. A $4 \mu F$ conductor is charged to 400 volts and then its plates are joined through a resistance of $1 k \Omega$. The heat produced in the resistance is
(a) $0.16 J$
(b) $1.28 J$
(c) $0.64 J$
(d) $0.32 J$
[1989]
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Answer:
Correct Answer: 49. (d)
Solution:
- (d) The energy stored in the capacitor
$=\frac{1}{2} C V^{2}=\frac{1}{2} \times 4 \times 10^{-6} \times(400)^{2}=0.32 J$
This energy will be converted into heat in the resistor.
