SATHEE: Electrostatic Potential and Capacitance

Electrostatic Potential and Capacitance - Result Question 40

42. The capacity of a parallel plate condenser is $10 μ F$ when the distance between its plates is $8 c m$ . If the distance between the plates is reduced to $4 c m$ then the capacity of this parallel plate condenser will be

(a) $5 μ F$

(b) $10 μ F$

(d) $40 μ F$

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Answer:

Correct Answer: 42. (c)

Solution:

$C^{'} = ? d^{'} = 4 c m$

$C = \frac{A ϵ_{0}}{d} \Rightarrow C \propto \frac{1}{d}$

If $d$ is halved then $C$ will be doubled.

Hence, $C^{'} = 2 C = 2 \times 10 μ F = 20 μ F$

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Electrostatic Potential and Capacitance - Result Question 40

42. The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reduced to 4cm then the capacity of this parallel plate condenser will be

Answer:

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42. The capacity of a parallel plate condenser is $10 μ F$ when the distance between its plates is $8 c m$ . If the distance between the plates is reduced to $4 c m$ then the capacity of this parallel plate condenser will be