SATHEE: Electrostatic Potential and Capacitance

Electrostatic Potential and Capacitance - Result Question 39

41. In a parallel plate capacitor, the distance between the plates is $d$ and potential difference across the plates is V. Energy stored per unit volume between the plates of capacitor is

(a) $\frac{Q^{2}}{2 V^{2}}$

(b) $\frac{1}{2} ε_{0} \frac{V^{2}}{d^{2}}$

(d) $\frac{1}{2} ε_{0} \frac{V^{2}}{d}$

[2001]

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Answer:

Correct Answer: 41. (b)

Solution:

(b) Energy stored per unit volume

$= \frac{1}{2} ε_{0} E^{2} = \frac{1}{2} ε_{0} (\frac{V}{d})^{2} = \frac{1}{2} ε_{0} \frac{V^{2}}{d^{2}} (∵ E = \frac{V}{d})$

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Electrostatic Potential and Capacitance - Result Question 39

41. In a parallel plate capacitor, the distance between the plates is d and potential difference across the plates is V. Energy stored per unit volume between the plates of capacitor is

Answer:

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41. In a parallel plate capacitor, the distance between the plates is $d$ and potential difference across the plates is V. Energy stored per unit volume between the plates of capacitor is