Electrostatic Potential and Capacitance - Result Question 33
35. Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be
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(a) $3 C, \frac{V}{3}$
(b) $\frac{C}{3}, 3 V$
(c) $3 C, 3 V$
(d) $\frac{C}{3}, \frac{V}{3}$
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Answer:
Correct Answer: 35. (b)
Solution:
- (b) In series combination of capacitors
$V _{\text{eff }}=V+V+V=3 V$
$\frac{1}{C _{eff}}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}$
$\Rightarrow C _{eff}=\frac{C}{3}$
Thus, the capacitance and breakdown voltage of the combination will be $\frac{C}{3}$ and $3 V$.
