Electrostatic Potential and Capacitance - Result Question 23

25. Two identical capacitors C1 and C2 of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor C1 using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy?

[NEET Odisha 2019]

(a) 25

(b) 75

(c) 0

(d) 50

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Answer:

Correct Answer: 25. (d)

Solution:

  1. (d)

=0.44×1010C2N1m2

Ui=12CV2

On switching key at point c

q0qC=qC2q=q0

q=(q02)Uf=12(q02)2×1C+12(q02)2×1CUf=14CV2 loss =50



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