Electrostatic Potential and Capacitance - Result Question 2
2. A short electric dipole has a dipole moment of $16 \times 10^{-9} C m$. The electric potential due to the dipole at a point at a distance of $0.6 m$ from the centre of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : [2020] $(\frac{1}{4 \pi \epsilon_0}=9 \times 10^{9} Nm^{2} / C^{2})$
(a) $200 V$
(b) $400 V$
(c) zero
(d) $50 V$
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Answer:
Correct Answer: 2. (a)
Solution:
- (a) Given,
Dipole moment of short electric dipole,
$p=16 \times 10^{-9} Cm$.
Distance from centre of dipole, $r=0.6 m$
Electric potential, $V=\frac{k p \cos \theta}{r^{2}}$
$\Rightarrow V=\frac{9 \times 10^{9} \times 16 \times 10^{-9} \times \cos 60}{0.36}=200 V$
