SATHEE: Electromagnetic Waves - Result Question 17

Electromagnetic Waves - Result Question 17

17. If $ε_{0}$ and $μ_{0}$ are the electric permittivity and magnetic permeability in vacuum, $ε$ and $μ$ are corresponding quantities in medium, then refractive index of the medium is

[1997]

(a) $\sqrt{\frac{ε}{ε_{0}}}$

(b) $\sqrt{\frac{ε_{0} μ}{ε μ_{0}}}$

(d) $\sqrt{\frac{ε μ}{ε_{0} μ_{0}}}$

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Answer:

Correct Answer: 17. (d)

Solution:

(d) We know that velocity of electromagnetic wave in vacuum

$(v_{0}) = \frac{1}{\sqrt{μ_{0} ε_{0}}}$ and velocity of

electromagnetic wave in medium is

$(v) = \frac{1}{\sqrt{μ ε}}$ .

Therefore refractive index of the medium

$(μ) = \frac{Vel. of E.M. wave in vacuum (v_{0})}{Vel. of E.M. wave in medium (v)}$

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Electromagnetic Waves - Result Question 17

17. If ε0 and μ0 are the electric permittivity and magnetic permeability in vacuum, ε and μ are corresponding quantities in medium, then refractive index of the medium is

Answer:

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17. If $ε_{0}$ and $μ_{0}$ are the electric permittivity and magnetic permeability in vacuum, $ε$ and $μ$ are corresponding quantities in medium, then refractive index of the medium is