Electromagnetic Induction - Result Question 8
8. In a coil of resistance $10 \Omega$, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil in
Weber is :
[2012M]
(a) 8
(b) 2
(c) 6
(d) 4
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Answer:
Correct Answer: 8. (b)
Solution:
- (b) The charge through the coil $=$ area of current-time $(i-t)$ graph
$q=\frac{1}{2} \times 0.1 \times 4=0.2 C$
$q=\frac{\Delta \phi}{R} \because$ Change in flux $(\Delta \phi)=q \times R$
$q=0.2=\frac{\Delta \phi}{10}$
$\Delta \phi=2$ Weber
